Total yield per unit of nutrient applied, without deduction of control yield.
partial_factor_productivity(yield, nutrient_applied, verbose = TRUE)Numeric vector. Partial factor productivity (kg yield per kg nutrient applied).
$$PFP = \frac{Y}{F}$$
partial_factor_productivity(yield = 4500, nutrient_applied = 120)
#> PFP computed (kg/kg).
#> [1] 37.5